VEDIC MATHS-107

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VEDIC MATHS

                           By OMKAR TENDOLKAR

Hello friends,

                      This is  post number 107 from the series of "Vedic maths" blogs. Here in this blog we will learn about "Applications of the Sutras & Sub-sutras - 7"

VEDIC MATHEMATIC :

"VEDIC MATHEMATICS" is the name given to the ancient system of mathematics, or, to be precise, a unique technique of calculations based on simple rules and principles, with which any mathematical problem be it arithmetic, algebra, geometry or trigonometry can be solved, hold your breath, orally!
What we call "Vedic Mathematics" is a mathematical elaboration of 'Sixteen Simple Mathematical formulae from the Vedas' as brought out by Sri Bharati Krishna Tirthaji.

Sutras: 

The system is based on 16 Vedic sutras or aphorisms, which are actually word formulae describing natural ways of solving a whole range of problems.
Some examples of sutras are "By one more than the one before", "All from 9 & the last from 10", and "Vertically & Crosswise". These 16 one-line formulae originally written in Sanskrit, which can be easily memorized, enables one to solve long mathematical problems quickly.

13. Shesanyankena Charamena ( The remainders by the last digit )

Example: 1/7

As seen earlier successive remainders are 1, 3, 2, 6, 4 and 5.
We will write them as 3, 2, 6, 4, 5 and 1.
Multiply them with the last digit of divisor (7): 21, 14, 42, 28, 35 and 7
Now take their last digits and that’s the final answer: 0.142857. (another interesting concept).

Example: 1/13


Successive remainders are 1, 10, 9, 12, 3 and 4.
We will write them as 10, 9, 12, 3, 4 and 1.
Multiply with the last digit of the divisor (3): 30, 27, 36, 9, 12 and 3.
Taking just last digits gives final answer: 0.076923.

14. Sopaantyadvayamantyam (The ultimate and twice the penultimate)

For the equation in the format 
 1       1       1        1  
AB + AC = AD + BC,
 the result is 2C(penultimate) + D(ultimate) = 0.

Example: 
        1                  1                  1                   1        
(x+2)(x+3) + (x+2)(x+4) = (x+2)(x+5) + (x+3)(x+4)

Applying the formula, 
2(x+4) + (x+5) = 0

or, x = -13 i.e. x = 13/3
             3

In next blog we will discuss about "Applications of the Sutras & Sub-sutras - 8".     

Are you excited for this?...
Then, please wait for it.
I will post my new blog in next week.

We will meet very soon through our next  blog. Till that stay connected, stay healthy and stay safe.

Thanks

for giving your valuable time.

Good day😊

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