VEDIC MATHS-40

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VEDIC MATHS

                           By OMKAR TENDOLKAR

Hello friends,

                      This is  post number 40 from the series of "Vedic maths" blogs. Here in this blog we will learn about "General Equations".

In all the blogs that we have discussed till now have deals with the arithmetical part of Vedic Mathematics. In this blog, we will study the algebraic part of this science. In Vedic Mathematics there are many simple formulae for solving different types of equations. Each such formula can be used for a particular category of equations. 

TYPE 1:

To solve an equation of the type ax + b = cx + d. 

Formula for this type of equation is,

              d - b

 x   =   ----------
              a - c

Examples:

1) Solve the equation 5x + 3 = 4x + 7 .

The equation is of the type ax + b = cx + d.

 where the values of a, b, c and d are 5, 3, 4 and 7 respectively. 

The value of x can be solved by using the formula as follow:

             d - b

 x   =   ----------
             a - c

              7 - 3

 X   =   ---------- = 4
              5 - 4

Solution:

x = 4.


2) Solve the equation 5x + 3 = 6x – 2

The equation is of the type ax + b = cx + d.

 where the values of a, b, c and d are 5, 3, 6 and -2 respectively. 

The value of x can be solved by using the formula as follow:

             d - b

 x   =   ----------
             a - c

             -2 - 3

 X   =   ---------- = 5.
              5 - 6

Solution:

x = 5.


TYPE 2:

 Now we have to solve equations of the type (x + a) (x + b) = (x + c) (x + d).

The value of x will be found using the formula:         

                cd - ab

 x   =   ------------------
            a + b - c - d

Examples:

1) Solve the equation (x + 1) (x + 3) = (x - 3) (x - 5)

The above equation is of the type (x + a) (x + b) = (x + c) (x + d). 

Thus the numbers 1, 3, -3 and -5 are represented by the letters a, b, c and d respectively. 

The value of x will be determined using the formula

                cd - ab

 x   =   ------------------
            a + b - c - d

                 15 - 3

 x   =   ------------------- = 1
            1 + 3 + 3 + 5

Solution:

x = 1.


(Q) Solve the equation (x + 7) (x + 12) = (x + 6) (x + 15)

The above equation is of the type (x + a) (x + b) = (x + c) (x + d). 

Thus the numbers 7, 12, 6 and 15 are represented by the letters a, b, c and d respectively. 

The value of x will be determined using the formula

                cd - ab

 x   =   ------------------
            a + b - c - d

                 90 - 84

 x   =   --------------------- = - 3
            7 + 12 - 6 - 15

Solution:

x = - 3.


The simplicity of this method can be vouched from examples given above.

In next blog we will discuss about "Simultaneous Linear Equation part-1".     


Are you excited for this?...
Then, please wait for it.
I will post my new blog in next week.

We will meet very soon through our next  blog. Till that stay connected, stay healthy and stay safe.

Thanks

for giving your valuable time.

Good day😊.

Location: Kudal, Maharashtra, India

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