VEDIC MATHS-45

   

VEDIC MATHS

                           By OMKAR TENDOLKAR

Hello friends,

                      This is  post number 45 from the series of "Vedic maths" blogs. Here in this blog we will learn about "Base Method of Division part-2"

The base method of division is having large contribution in Vedic Mathematics. The name Base method is given by Vedic Mathematics in western countries. 

The study of division is divided in two parts. In this post we will study the Base Method and in the next blogs we will study the Paravartya Method of division.

We have seen the applications of the Base Method in multiplication and squaring of numbers in previous blogs. In this method we use power of ten as a base and then calculate the difference between the base and the given number. The same concept will be used for division.

Reference:

We had already learn about "Base Method of Division part-1" our previous blog. If you have missed my last blog then please visit "VEDIC MATHS-44".

Examples:

1.Divide 502 by 99

100

99            5 | 02
01               | 05                   
                   |
                   |
             ------------
                5 | 07  
  

Answer:
502 divided by 99
quotient is 5
remainder is 7.

2. Divide 617 by 95

100

95             6 | 17
05                | 30                    
                    |
                    |
             ---------------
                 6 | 47     

Answer:

617 divided by 95 
quotient is 6
remainder is 47.

In all the examples that we have seen above, we split the dividend into LHS and RHS. However, there was only one digit in the LHS. We will now take a look at how to solve examples where the dividend is big and the LHS has more than one digit.

3. Divide 123 by 9

10

9           1 2 | 3
1              1 |                     
                   |
                   |
             ----------
              1   | 

  1. The base 10 has one zero and therefore we split the dividend in such a way that the RHS has one digit.
  2. Now we are left with two digits on the LHS.
  3. We bring down the first digit 1 as it is.
  4. We multiply the 1 with the difference 1 and put the answer below the second digit of the dividend.
  5. The second digit of the dividend is 2 and we add 1 to it. The total is 3.

10

9            12 | 3
1              1 | 3                     
                   |
                   |
             ------------
              13 | 6

  1. We now multiply the total 3 with the difference 1 and write the product, viz. 3 below the third digit of the dividend.
  2. The total is 6.
Answer:
123 divided by 9 
quotient is 13
remainder is 6.

4. Divide 1234 by 98

100

98                  1 2 | 3 4
02                     0 | 2                     
                            | 0 4
                            | 
                 --------------------
                      1 2 | 5 8
  1. We bring down 1 and multiply it with 02. The product 02 is written down from the second digit of the dividend.
  2. We now add 2 plus 0 downwards and get the second digit of the quotient. The answer is 2.
  3. We multiply 2 with 02 and the final answer 04 is written down from the third digit of the dividend.
  4. We add up the numbers on the RHS from the extreme right column. The total of 4 + 4 is 8. We come to the column on the left and add 3 + 2 + 0 = 5.
  5. Hence, the product is 12 and the remainder is 58.
(In the above example, the difference of 100 and 98 is taken as 02. If we take the difference as 2 instead of 02 we will get incorrect answer.)

Answer:
1234 divided by 98 
quotient is 12
remainder is 58.


Find Division of following:

  1. 2122 / 97, then quotient is 21 and remainder is 85.
  2. 10113 / 998, then quotient is 10 and remainder is 133.
  3. 1005 / 99, then quotient is 10 and remainder is 15.
The simplicity of this method can be vouched from examples given above.


You may try following example:

Find Division of followings

1. 465 / 98

2. 3887 / 98

3. 4007 / 997

You may answer this in comment box. You may ask your any query or doubt in comment box. I will try to resolve as early as possible.

In next blog we will discuss about "Example of Base Method of Division part-3".     


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