VEDIC MATHS-109

 

VEDIC MATHS

                           By OMKAR TENDOLKAR

Hello friends,

                      This is  post number 109 from the series of "Vedic maths" blogs. Here in this blog we will learn about "Applications of the Sutras & Sub-sutras - 9"

VEDIC MATHEMATIC :

"VEDIC MATHEMATICS" is the name given to the ancient system of mathematics, or, to be precise, a unique technique of calculations based on simple rules and principles, with which any mathematical problem be it arithmetic, algebra, geometry or trigonometry can be solved, hold your breath, orally!

What we call "Vedic Mathematics" is a mathematical elaboration of 'Sixteen Simple Mathematical formulae from the Vedas' as brought out by Sri Bharati Krishna Tirthaji.

Sub-Sutras: 

The system is based on 13 Vedic sutras or aphorisms, which are actually word formulae describing natural ways of solving a whole range of problems.

Some examples of sutras are "Anurupyena", "Antyayor Desakepi", and "Antyayoreva". These 13 one-line formulae originally written in Sanskrit, which can be easily memorized, enables one to solve long mathematical problems quickly.

1. Anurupyena ( Proportionality )

This Sutra is highly useful to find products of two numbers when both of them are near the Common bases i.e powers of base 10. For example:

Example: 

i) 46 x 43
We take 50 as a base point because it is the nearest powers of base 10.
46 = 50 – 4
43 = 50 – 7

Multiplying the difference from 50 to the numbers,

4 x 7 = 28 …… (a)
From cross subtraction,
43 – 4 = 39 or 46 – 7 = 39……. (b)
Adding (a) with the base i.e., 28+50 = 78 (goes on right hand side)
Dividing 39 by 2 give 19 with remainder 1. (goes on left hand side)
Thus, 46 x 43 = 1978

ii) 56 x 53
56 = 50 + 6
53 = 50 + 3
56 x 53 = (56 + 3) or (53 + 6), (6 x 3) + 50
= 59,18 = 59/2, 18 = 2968

( For  more information refer -: VEDIC MATHS-35 )

2. Adyamadyenantya – mantyena (The first by the first and the last by the last )

Example: 2x² + 5x -3

Divide the first term’s coefficient (2) of the equation by 1st term of factor(1) and divide the last term of equation (-3) by 2nd term of factor (3).  So, 2nd factor: 2x-1

In next blog we will discuss about "Applications of the Sutras & Sub-sutras - 10".     

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