VEDIC MATHS-95
VEDIC MATHS
By OMKAR TENDOLKAR
Hello friends,
This is post number 95 from the series of "Vedic maths" blogs. Here in this blog we will learn about "Quadratic Equations-II"
Reference:
We had already learn about "Quadratic Equations-I" in our previous blog. If you have missed my last blog then please visit "VEDIC MATHS-94".
Quadratic Equations:
Here in this post we will learn how to solve quadratic equations using Vedic maths.
Special Case of Quadratic Equations—Reciprocals:
Case A
1. Here we have our first sum: x + 1/x = 17/4.
left-hand side is the sum of two reciprocals, so we’ll simply split 17/4 the on the right-hand side into 4 + 1/4.
And what we get is x = 4 or 1/4.
Answer:
x = 4 or x = 1/4.
2. Here we have our first sum: x + 1/x = 26/5.
left-hand side is the sum of two reciprocals, so we’ll simply split 26/5 the on the right-hand side into 5 + 1/5.
And what we get is x = 5 or 1/5.
Answer:
x = 5 or x = 1/5.
3. x/(x+1) + (x+1)/x = 82/9.
left-hand side is the sum of reciprocals. Therefore, let’s split the right-hand side into 9 + 1/9.
x/(x+1) = 9
x = 9x +9
x - 9x = 9
- 8x = 9
x = -9/8
or
x/(x+1) = 1/9
9x = x +1
9x - x = 1
8x = 1
x = 1/8
Answer:
x = -9/8 & x = 1/8.
4. (x+1)/(x+2) + (x+2)/(x+1) = 37/6.
left-hand side is the sum of reciprocals. Therefore, let’s split the right-hand side into 6 + 1/6.
(x+1)/(x+2) = 6
x + 1 = 6x + 12
x - 6x = 12 -1
- 5x = 11
x = -11/5
or
(x+1)/(x+2) = 1/6
6x + 6 = x + 2
6x - x = 2 - 6
5x = -4
x = -4/5
Answer:
x = -11/5 & x = -4/5.
The simplicity of this method can be vouched from examples given above.
You may try following examples.
1. x + 1/x = 50/7.
2. x/(x+1) + (x+1)/x = 50/7.
3. (x+1)/(x+2) + (x+2)/(x+1) = 26/5.
In next blog we will discuss about "Quadratic Equation-III".
Are you excited for this?...
Then, please wait for it.
I will post my new blog in next week.
We will meet very soon through our next blog. Till that stay connected, stay healthy and stay safe.
Thanks
for giving your valuable time.
Good day😊
Comments
Post a Comment